Java Program To Check Leap Year | Java Logic

In this program, you'll learn to check if the given year is a leap year or not. This is checked using a if else statement.

To understand this example, you should have the knowledge of the following Java programming topics:

   • Java Operators

   • Java if...else Statement

A leap year is exactly divisible by 4 except for century years (years ending with 00). The century year is a leap year only if it is perfectly divisible by 400.

Example: Java Program to Check a Leap Year

Curious Faizan | Java Algorithm

01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36	public class Main {     public static void main(String[] args) {       // year to be checked     int year = 1900;     boolean leap = false;       // if the year is divided by 4     if (year % 4 == 0) {         // if the year is century       if (year % 100 == 0) {           // if year is divided by 400         // then it is a leap year         if (year % 400 == 0)           leap = true;         else           leap = false;       }               // if the year is not century       else         leap = true;     }           else       leap = false;       if (leap)       System.out.println(year + " is a leap year.");     else       System.out.println(year + " is not a leap year.");   } }

Output

1900 is not a leap year.

In the above example, we are checking if the year 1900 is a leap year or not. Since 1900 is a century year (ending with 00), it should be divisible by both 4 and 400 to be a leap year.

However, 1900 is not divisible by 400. Hence, it is not a leap year.

Now, let's change the year to 2012. The output will be

2012 is a leap year.

Here, 2012 is not a century year. Hence, to be a leap year, it needs to be divisible by only 4.

Since 2012 is divisible by 4, it is a leap year.

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